d and f-Block ElementsMedium

Question

'Spin only' magnetic moment is same for which of the following ions?

A. ${Ti}^{3 +}$

B. ${Cr}^{2 +}$

C. ${Mn}^{2 +}$

D. ${Fe}^{2 +}$

E. ${Sc}^{3 +}$

Choose the most appropriate answer from the options given below.

Options

A.B and C only
B.A and D only
C.B and D only
D.A and E only

Solution

Sol. [Key Concept: Spin only magnetic moment]

For the spin only approximation, μ = √[n(n + 2)] μB, where n is the number of unpaired electrons. Ti³⁺ is 3d¹ with 1 unpaired electron; Cr²⁺ is 3d⁴ with 4; Mn²⁺ is 3d⁵ with 5; high spin Fe²⁺ is 3d⁶ with 4; Sc³⁺ is 3d⁰ with 0. Cr²⁺ and Fe²⁺ therefore both have μ = √24 μB ≈ 4.90 μB. These are B and D, option (3).

Ions No. of unpaired electrons Configuration
$${Ti}^{3 +}$$ 1 $$3d^{1}$$
$${Cr}^{2 +}$$ 4 $$3d^{4}$$
$${Mn}^{2 +}$$ 5 $$3d^{5}$$
$${Fe}^{2 +}$$ 4 $$3d^{6}$$
$${Sc}^{3 +}$$ 0 $$3d^{0}$$

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