d and f-Block ElementsMedium
Question
'Spin only' magnetic moment is same for which of the following ions?
A. ${Ti}^{3 +}$
B. ${Cr}^{2 +}$
C. ${Mn}^{2 +}$
D. ${Fe}^{2 +}$
E. ${Sc}^{3 +}$
Choose the most appropriate answer from the options given below.
Options
A.B and C only
B.A and D only
C.B and D only
D.A and E only
Solution
Sol. [Key Concept: Spin only magnetic moment]
For the spin only approximation, μ = √[n(n + 2)] μB, where n is the number of unpaired electrons. Ti³⁺ is 3d¹ with 1 unpaired electron; Cr²⁺ is 3d⁴ with 4; Mn²⁺ is 3d⁵ with 5; high spin Fe²⁺ is 3d⁶ with 4; Sc³⁺ is 3d⁰ with 0. Cr²⁺ and Fe²⁺ therefore both have μ = √24 μB ≈ 4.90 μB. These are B and D, option (3).
| Ions | No. of unpaired electrons | Configuration |
|---|---|---|
| $${Ti}^{3 +}$$ | 1 | $$3d^{1}$$ |
| $${Cr}^{2 +}$$ | 4 | $$3d^{4}$$ |
| $${Mn}^{2 +}$$ | 5 | $$3d^{5}$$ |
| $${Fe}^{2 +}$$ | 4 | $$3d^{6}$$ |
| $${Sc}^{3 +}$$ | 0 | $$3d^{0}$$ |
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