Atomic StructureMedium
Question
Match List I with List II.
| List I (Spectral Lines of Hydrogen for transitions from) | List II (Wavelengths (nm)) | ||
|---|---|---|---|
| A. | $n_{2} = 3$ to $n_{1} = 2$ | I. | 410.2 |
| B. | $n_{2} = 4$ to $n_{1} = 2$ | II. | 434.1 |
| C. | $n_{2} = 5$ to $n_{1} = 2$ | III. | 656.3 |
| D. | $n_{2} = 6$ to $n_{1} = 2$ | IV. | 486.1 |
Choose the correct answer from the options given below:
Options
A.A-IV, B-III, C-I, D-II
B.A-I, B-II, C-III, D-IV
C.A-II, B-I, C-IV, D-III
D.A-III, B-IV, C-II, D-I
Solution
Sol. [Key Concept: Matching physical quantities with expressions]
Energy difference $\Delta E = \frac{hc}{\lambda}$
$$\begin{matrix} & \ \therefore\lambda \propto \frac{1}{\Delta E} \\ & \ (\Delta E)_{6 - 2} > (\Delta E)_{5 - 2} > (\Delta E)_{4 - 2} > (\Delta E)_{3 - 2} \\ & \lambda_{6 - 2} < \lambda_{5 - 2} < \lambda_{4 - 2} < \lambda_{3 - 2} \\ & \text{~}\text{A-III, B-IV, C-II, D-I}\text{~} \end{matrix}$$
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