Nuclear Physics and RadioactivityHard
Question
de-Broglie wavelength of an electron in the nth Boher orbit is λn and the angular momentum is Jn, then.
Options
A.Jn ∝ λn
B.λn ∝ 
C.λn ∝ Jn2
D.None of these
Solution
Jn = 
⇒ nλν = 2π 2(r0n2)
So Jn ∝ λn ⇒ λn = (2πr0)n
⇒ nλν = 2π 2(r0n2)So Jn ∝ λn ⇒ λn = (2πr0)n
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