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Question

A protein undergoes reversible thermal denaturation from its initial state $\mathbf{N}$ to denatured state $\mathbf{D}$ according to $\mathbf{N} \rightleftharpoons \mathbf{D}$. At $60^{\circ}C$, the concentrations of both $\mathbf{N}$ and $\mathbf{D}$ are equal at equilibrium, and the standard enthalpy change of denaturation is $666\text{ }kJ{\text{ }mol}^{- 1}$. The standard entropy change ( $\Delta S^{\circ}$ in $kJK^{- 1}{\text{ }mol}^{- 1}$ ) of the protein upon denaturation at 60°C is closest to

Options

A.333.0
B.11.1
C.2.0
D.2000.0

Solution

Sol. [Key Concept: Thermodynamics of reversible protein denaturation]

$$\begin{matrix} & \Delta S = \frac{\Delta H}{\text{ }T} \\ & \ = \frac{666}{333} \\ & \ = 2\text{ }kJ{\text{ }K}^{- 1}{\text{ }mol}^{- 1} \end{matrix}$$

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