CapacitanceMedium
Question
Five capacitors of capacitances
$C_{1} = C_{2} = C_{3} = C_{4} = 10\mu\text{ }F$ and $C_{5} = 2.5\mu\text{ }F$ are connected as shown, along with a battery of 50 V.
The equivalent capacitance and the charges on each capacitor respectively are:
Options
A.$\ 5\mu\text{ }F,125\mu C$ on $C_{1}$ to $C_{4}$ and $25\mu C$ on $C_{5}$
B.$\ 5\mu\text{ }F,125\mu C$ on all capacitors
C.$5\mu\text{ }F,250\mu C$ on all capacitors
D.$\ 4\mu\text{ }F,250\mu C$ on $C_{1}$ to $C_{4}$ and $125\mu C$ on $C_{5}$
Solution
Sol. [Key Concept: Capacitor network — series/parallel equivalents] 
$$\begin{matrix} & C_{eq} = 2.5 + 2.5 = 5\mu{\text{ }F}^{'} \\ & q_{1} = q_{2} = q_{3} = q_{4} = 2.5 \times 50 = 125\mu C \\ & q_{5} = 2.5 \times 50 = 125\mu C \end{matrix}$$
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