A dielectric slab of thickness d is inserted in a parallel plates capacitor whose negative plate is

Question

A dielectric slab of thickness d is inserted in a parallel plates capacitor whose negative plate is at x = 0 and positve plates is x = 3d. The slab is equidistant from the plates. The capacitor is given some charge. As x goes from 0 to 3d

Accepted Answer

The magnitude and direction of electric field at different points are shown in the figure. The direction of the electric field remains the same. Hence, option (b) is correct. Similarly, electric lines always flow from higher to lower potential, therefore, electric potential increases continuously as we move from x = 0 to x = 3d.
Therefore, option (c) is also correct. The variation of electric field (E) and potential (V) with x will be as follows

OA ||BC and (slope)_OA > (slope)_AB
Because E_{o - d} = E_{2d - 3d}
and E_{o - d} > E_{d - 2d}.

Question

Options

Solution

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