Coordination CompoundMedium

Question

The correct order of the wavelength of light absorbed by the following complexes is,

A. $\left\lbrack Co\left( {NH}_{3} \right)_{6} \right\rbrack^{3 +}$

B. $\left\lbrack Co(CN)_{6} \right\rbrack^{3 -}$

C. $\left\lbrack Cu\left( H_{2}O \right)_{4} \right\rbrack^{2 +}$

D. $\left\lbrack Ti\left( H_{2}O \right)_{6} \right\rbrack^{3 +}$

Choose the correct answer from the options given below:

Options

A.$B < D < A < C$
B.B $<$ A $<$ D $<$ C
C.C $<$ D $<$ A $<$ B
D.C $<$ A $<$ D $<$ B

Solution

Sol. [Key Concept: Order of wavelength of light absorbed by complexes (CFSE / Δₒ)]

$\ \lambda \propto \frac{1}{\text{~}\text{strength of ligand}\text{~}}$

$$\lambda \propto \frac{1}{\text{~}\text{splitting}\text{~}} $$A. $\left\lbrack Co\left( {NH}_{3} \right)_{6} \right\rbrack^{3 +}\ ;\ 475\text{ }nm$

B. $\left\lbrack Co(CN)_{6} \right\rbrack^{3 -}\ ;\ 310\text{ }nm$

C. $\left\lbrack Cu\left( H_{2}O \right)_{4} \right\rbrack^{2 +}\ ;\ 600\text{ }nm$

D. $\left\lbrack Ti\left( H_{2}O \right)_{6} \right\rbrack^{3 +}\ ;\ 498\text{ }nm$

Order of $\lambda = C > D > A > B$

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