Coordination CompoundHard
Question
The compound which is not coloured is
Options
A.K4Fe(CN)6
B.K3Fe(CN)6
C.Na2CdCl4
D.Na2CuCl4
Solution
In Na2CdCl4, Cd has oxidation state + 2, so its electronic configuration is 4d10 4s10. or all the 4 d orbitals are fully filled.
Hence, there will not be d-d transition resulting in colour. So,it is colourless.
Hence, there will not be d-d transition resulting in colour. So,it is colourless.
Create a free account to view solution
View Solution FreeMore Coordination Compound Questions
50 ml of 0.2 M solution of a compound with empirical formula CoCl3.4NH3 on treatment with excess of AgNO3(aq) yields 1.4...The coordination number and the oxidation state of the element ′E′ in the complex [E(en)2(C2O4)]NO2 (where (...The complex K4[Zn(CN)4(O2)2] is oxidised into K2[Zn(CN)4(O2)2], then which of the following is correct ?...In which of the following pairs both the complexes show optical isomerism ?...Which of the following ions are optically active?...