ProbabilityHardBloom L3

Question

A seven-digit number of $a_{1}a_{2}a_{3}a_{4}a_{5}a_{6}a_{7}$ (all digits distinct) is formed randomly. The probability that number formed satisfy $a_{1} > a_{2} > a_{3} < a_{4} < a_{5} < a_{6} < a_{7}$ is

Options

A.$\frac{11}{1572}$
B.$\frac{1}{168}$
C.$\frac{7}{1512}$
D.$\frac{5}{1512}$

Solution

Sol. [Key Concept: $7$-digit number with distinct digits: count favorable arrangements.]

7 digits are distinct and $a_{3}$ is the smallest

∴ Number of favorable ways $=$

$$\begin{matrix} P & \ = \frac{\left( \frac{10 \times 9 \times 8 \times 6 \times 5}{3 \times 2 \times 2} \right)}{9 \times 9 \times 8 \times 7 \times 6 \times 5 \times 4} \\ & \ = \frac{5}{1512} \end{matrix}$$

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