ProbabilityHard
Question
In a purse there are 10 coins, all 5 paise except one which is a rupee. In another purse there are 10 coins all 5 paise. 9 coins are taken out from the former purse & put into the latter & then 9 coins are taken out from the latter & put into the former. Then the chance that the rupee is still in the first purse is:
Options
A.9/19
B.10/19
C.4/9
D.none
Solution
10 coins 9 5 paisa 10 coins 5 paisa
1 1 Rs.
p = p (1 Rs. transfered + Back transfered) + p (1 Rs. not transfered)
method 2 when 1 Rs coin is in second purse and did not came back in first purse this prob. =
⇒ Required probability = 1 -
1 1 Rs.
p = p (1 Rs. transfered + Back transfered) + p (1 Rs. not transfered)
method 2 when 1 Rs coin is in second purse and did not came back in first purse this prob. =
⇒ Required probability = 1 -
Create a free account to view solution
View Solution FreeMore Probability Questions
A bag contains 4 tickets numbered 1, 2, 3, 4 and another bag contains 6 tickets numbered 2, 4, 6, 7, 8, 9. One bag is ch...Urn A contains 6 red & 4 black balls and urn B contains 4 red & 6 black balls. One ball is drawn at random from urn A & ...Two dice are thrown thrice. The probability that first throw shows 10, second 11 and third 12 will be-...The probability of solving a problem by A and B are 1/4 and 2/3 respectively. If A and B work independently, then the pr...If A and B be any two events, then P (AB) equals-...