GravitationMedium

Question

A body weighs 48 N on the surface of the earth. The gravitational force experienced by the body due to the earth at a height equal to one-third the radius of the earth from its surface is:

Options

A.16 N
B.27 N
C.32 N
D.36 N

Solution

$W = mg$ and $g = \frac{GM}{R^{2}},g_{h} = \frac{GM}{(R + h)^{2}}$

$$\begin{matrix} & \ \Rightarrow \frac{W_{h}}{W} = \frac{mg_{h}}{mg} = \frac{g_{h}}{g} = \frac{R^{2}}{(R + h)^{2}}\ \left( h = \frac{R}{3} \right) \\ & \ \Rightarrow \frac{W_{h}}{W} = \frac{R^{2}}{\left( R + \frac{R}{3} \right)^{2}} = \frac{R^{2}}{\left( \frac{4R}{3} \right)^{2}} = \frac{9}{16} \\ & \ \Rightarrow W_{h} = \frac{9}{16}W = \frac{9}{16} \times 48\ \lbrack W = 48\text{ }N\rbrack \\ & \ = 27\text{ }N \end{matrix}$$

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