GravitationHard
Question
The escape velocity from the earth is about 11 km/second. The escape velocity from a planet having twice the radius and the same mean density as the earth, is :-
Options
A.22 km/sec
B.11 km/sec
C.5.5 km/sec
D.15.5 km/sec
Solution
Ve = 
∴ ve ∝ R if ρ = constant
Since the planet having double radius in comparison to earth therefore the escape velocity becomes twice i.e. 22 km/s.
∴ ve ∝ R if ρ = constant
Since the planet having double radius in comparison to earth therefore the escape velocity becomes twice i.e. 22 km/s.
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