CircleHardBloom L3

Question

From $(3,4)$ chords are drawn to the circle $x^{2} + y^{2} - 4x = 0$. The locus of the mid points of the chords is:

Options

A.$x^{2} + y^{2} - 5x - 4y + 6 = 0$
B.$x^{2} + y^{2} + 5x - 4y + 6 = 0$
C.$x^{2} + y^{2} - 5x + 4y + 6 = 0$
D.$x^{2} + y^{2} - 5x - 4y - 6 = 0$

Solution

[Key Concept: Midpoints of chords from a fixed external point lie on a circle — set $T = S_{1}$.]

Locus is Arc of the circle with $OP$ as diameter intercepted by the given circle.i.e.,

$$(x - 2)(x - 3) + y(y - 4) = 0$$

Create a free account to view solution

View Solution Free
Topic: Circle·Practice all Circle questions

More Circle Questions