CircleEasy
Question
If the pair of lines ax2 + 2(a + b)xy + by2 = 0 lie along diameters of a circle and divide the circle into four sectors such that the area of one of the sectors is thrice the area of another sector then
Options
A.3a2 - 10ab + 3b2 = 0
B.3a2 - 2ab + 3b2 = 0
C.3a2 + 10ab + 3b2 = 0
D.3a2 + 2ab + 3b2 = 0
Solution
⇒ (a + b)2 = 4(a2 + b2 + ab)
⇒ 3a2 + 3b2 + 2ab = 0.
Create a free account to view solution
View Solution FreeMore Circle Questions
If the two circles, x2 + y2 + 2g1x + 2f1y = 0 and x2 + y2 + 2g2x + 2f2y = 0 touches each other, then -...The equation of the normal to the circle x2 + y2 − 8x − 2y + 12 = 0 at the points whose ordinate is −1...Let $y = x$ be the equation of a chord of the circle $\mathbf{C}_{1}$ (in the closed half-plane $x \geq 0$ ) of diameter...A circle is inscribed into a rhombus $ABCD$ with one angle $60^{\circ}$. The distance from the centre of the circle to t...If a circle passes through the point (1, 2) and cuts the circle x2 + y2 = 4 orthogonally, then the equation of the locus...