CircleHard
Question
If the pair of lines ax2 + 2(a + b)xy + by2 = 0 lie along diameters of a circle and divide the circle into four sectors such that the area of one of the sectors is thrice the area of another sector then
Options
A.3a2 - 10ab + 3b2 = 0
B.3a2 - 2ab + 3b2 = 0
C.3a2 + 10ab + 3b2 = 0
D.3a2 + 2ab + 3b2 = 0
Solution
⇒ (a + b)2 = 4(a2 + b2 + ab)
⇒ 3a2 + 3b2 + 2ab = 0.
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