CircleHardBloom L3
Question
If the area of the quadrilateral formed by the tangents from the origin to the circle $x^{2} + y^{2} + 6x - 10y + c = 0$ and the radii corresponding to the points of contact is 15 , then a value of $c$ is:
Options
A.9
B.4
C.5
D.25
Solution
[Key Concept: Tangents from the origin + the two radii form a kite of area (tangent length)$\times$radius; tangent length $= \sqrt{S_{1}}$.]
Area of quadrilateral
$$15 = \sqrt{34 - C}\sqrt{C}$$
$$\begin{matrix} & C^{2} - 34C + 225 = 0 \\ & \ (C - 25)(C - 9) = 0 \\ & C = 9,25 \end{matrix}$$
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