Question
Given below are two statements:
Statement-I: Aluminium is more electropositive than thallium as the standard electrode potential value of $E_{{Al}^{3 +}/Al}^{o}$ is negative and $E_{{Tl}^{3 +}/Tl}^{o}$ is positive.
Statement-II: The sum of first three ionization enthalpies of boron is very high when compared to that of aluminium. Due to this reason boron forms covalent compounds only and aluminium forms ${Al}^{3 +}$ ion.
In the light of the above statements, choose the correct answer from the options given below.
Options
Solution
Sol. [Key Concept: Compare standard electrode potentials (Al more electropositive) and the sum of the first three ionization enthalpies (much higher for boron), showing both statements true.]
$$E_{{Al}^{3 +}/Al}^{0} = - 1.66\text{ }VE_{{Tl}^{3 +}/Tl}^{o} = + 1.26\text{ }V$$
For B: IE $+ {IE}_{2} + {IE}_{3} = 801 + 2427 + 3659 = 6887\text{ }kJ$
Both statements are true
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