20 mL of a solution of acetic acid required 28.4 mL of 0.1 M NaOH for its neutralization. A solution

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20 mL of a solution of acetic acid required 28.4 mL of 0.1 M NaOH for its neutralization. A solution (X) was prepared by mixing 20 mL of the above acetic acid and 14.2 mL of 0.1 M NaOH solution. What is the pH of the solution (X) ? $\left( {pK}_{a} \right.\ $ value of acetic acid is 4.75).

Accepted Answer

Sol. [Key Concept: $14.2$ mL is exactly half of the $28.4$ mL needed for full neutralisation, giving an acidic buffer at half-equivalence; apply Henderson's equation.]In experiment 1, 28.4 ml of NaOH is required for complete neutralisation, therefore for 14.2 ml , half equivalence point will be achieved to form acidic buffer.

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