Periodic TableMedium

Question

The correct statements among the following are,

A. $Mo(VI)$ and $W(VI)$ are less stable than $Cr(VI)$.

B. ${Ce}^{4 +}$ and ${Tb}^{4 +}$ are oxidant while ${Eu}^{2 +}$ and ${Yb}^{2 +}$ are reductant.

C. Cm and Am have seven unpaired electrons.

D. Actinoid contraction is greater from element to element than lanthanoid contraction.

Choose the correct answer from the options given below :

(1) A and B Only

(2) C and D Only

(3) B and D Only

(4) A and C Only

Solution

Sol. [Key Concept: Check each: Mo(VI)/W(VI) are more stable than Cr(VI); Ce$4 +$/Tb$4 +$ oxidise while Eu$2 +$/Yb$2 +$ reduce (B) and actinoid contraction $>$ lanthanoid (D).]

(A) $Mo(VI)$ & $W(VI)$ more stable than $Cr(VI)$

(B) In lanthanoids +3 oxidation state is more stable hance +4 ions act as oxidising agents and +2 ions act as reducing agents.

(C) $Cm - \lbrack Rn\rbrack 5f^{7}6{\text{ }d}^{1}7{\text{ }S}^{2} = 8$ unpaired electrons

$Am - \lbrack Rn\rbrack 5f^{7}6{\text{ }S}^{2} = 7$ unpaired electrons

(D) Actinoid contraction is more than lanthanoid contraction

Create a free account to view solution

View Solution Free
Topic: Periodic Table·Practice all Periodic Table questions

More Periodic Table Questions