Periodic TableHard
Question
Consider the elements $N,P,O,S,Cl$ and F . The number of valence electrons present in the elements with most and least metallic character from the above list is respectively.
Options
A.7 and 5
B.5 and 6
C.5 and 7
D.6 and 7
Solution
Least metallic $= F$, valence electrons $= 7$
Most metallic $= P$, valence electrons $= 5$
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