Periodic TableHard

Question

Consider the elements $N,P,O,S,Cl$ and F . The number of valence electrons present in the elements with most and least metallic character from the above list is respectively.

Options

A.7 and 5
B.5 and 6
C.5 and 7
D.6 and 7

Solution

Least metallic $= F$, valence electrons $= 7$

Most metallic $= P$, valence electrons $= 5$

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