Periodic TableMedium
Question
The correct order of $C,N,O$ and F in terms of second ionisation potential is
Options
A.F $< N < C < O$
B.C $<$ O $<$ N $<$ F
C.C $<$ N $<$ F $<$ O
D.C $<$ F $<$ N $<$ O
Solution
To compare second ionization potential configuration of mono-cation is observed
| $$C^{+}$$ | $$N^{+}$$ | $$O^{+}$$ | $$F^{+}$$ |
|---|---|---|---|
| $$\lbrack He\rbrack$$ | $$\lbrack He\rbrack$$ | $$\lbrack He\rbrack 2{\text{ }s}^{2}2p^{3}$$ | $$\lbrack He\rbrack 2{\text{ }s}^{2}2p^{4}$$ |
| $$2{\text{ }s}^{2}{sp}^{1}$$ | $$2{\text{ }s}^{2}2p^{2}$$ | Half-filled stable. |
Half-filled
stable.
$2^{\text{nd~}}$ IE order
O $>$ F $>$ N $>$ C
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