The equation of motion of a particle is given by $x = asin(50t + \pi/3)cm$. The particle will come t

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The equation of motion of a particle is given by $x = asin(50t + \pi/3)cm$. The particle will come to rest at time $t_{1}$ and it will have zero acceleration at time $t_{2}$. The $t_{1}$ and $t_{2}$ respectively are $\_\_\_\_$ .

Accepted Answer

Sol. [Key Concept: Rest at the extreme position and zero acceleration at the mean; solve for the two times.]Phase of the motion of particle is as follows :$V = 0$, when particle cross A .$$	herefore t_{1} = \frac{\pi}{6\omega} = \frac{\pi}{300} $$$a = 0$, when particle cross B .$$	herefore t_{2} = \frac{2\pi}{3\omega} = \frac{\pi}{75}$$

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