SHMHard
Question
The amplitude of a particle SHM about O is 10cm. Then :
Options
A.when the kinetic energy is 0.64 times of its max. kinetic energy its displacement is 6cm from O
B. when the displacement is 5 cm from O its kinetic energy is 0.75 times maximum kinetic energy
C.Its total energy energy of SHM at any point is equal to its maximum,
D.Its speed if half the maximum speed when its displacement is half the maximum displacement
Solution
y = 10 sin (ωt + φ)
Maximum KE =
mω2A2
⇒
mω2A2 = 
mω2 (A2 - x2)
⇒ 64A2 = (A2 - x2)100 ⇒ x = 0.6 A
⇒
mω2(A2 -x2) = 
mω2A2 × x
⇒ x = .75 means 75% of energy
Maximum KE =
mω2A2⇒
mω2A2 = mω2 (A2 - x2)⇒ 64A2 = (A2 - x2)100 ⇒ x = 0.6 A
⇒
mω2(A2 -x2) = mω2A2 × x⇒ x = .75 means 75% of energy
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