Angular momentum of an electron in a hydrogen atom is $\frac{3 ext{ }h}{\pi}$, then the energy of t

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Angular momentum of an electron in a hydrogen atom is $\frac{3	ext{ }h}{\pi}$, then the energy of the electron is $\_\_\_\_$ eV .

Accepted Answer

Sol. [Key Concept: $L = nh/2\pi$ fixes $n$; then $E = - 13.6/n^{2}$ eV.]$$L = \frac{nh}{2\pi}$$$$\begin{matrix} & \frac{3	ext{ }h}{\pi} = \frac{nh}{2\pi} \ & n = 6 \ & E = \frac{- 13.6}{n^{2}}eV \ & \ = \frac{- 13.6}{6^{2}} \approx - 0.38eV \end{matrix}$$

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