Atomic StructureHard
Question
An alphanucleus of energy 1/2 mv2 bombards a heavy nuclear target of charge Ze. Then the distance of closest approach for the alpha nucleus will be proportional to
Options
A.
B.v2
C.
D.
Solution
At the distance of closest approach d,
Kinetic energy = Potential energy
mv2 = 
where,
Ze = charge of target nucleus
2e = charge of alpha nucleus
mv2 = kinetic energy of alpha nucleus of mass m moving with velocity v.
or,
∴ d ∝ 
.
Kinetic energy = Potential energy
mv2 = where,
Ze = charge of target nucleus
2e = charge of alpha nucleus
mv2 = kinetic energy of alpha nucleus of mass m moving with velocity v. or,
∴ d ∝ .Create a free account to view solution
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