Coordination CompoundMedium
Question
Match List - I with List - II.
| List - I | List - II | ||
|---|---|---|---|
Chromium (III) Complexes $(\mathbf{en} =$ ethylene diamine $)$ |
$$\Delta_{\mathbf{0}}\left( \mathbf{cm}^{- \mathbf{1}} \right)$$ | ||
| A. $\ \left\lbrack Cr(CN)_{6} \right\rbrack^{3 -}$ | I. | 15,060 | |
| B. $\ \left\lbrack CrFF_{6} \right\rbrack^{3 -}$ | II. | 17,400 | |
| C. $\left. \ \ \left\lbrack Cr\left( H_{2}O \right)_{6} \right) \right\rbrack^{3 +}$ | III. | 22,300 | |
| D. $\ \left\lbrack Cr(en)_{3} \right\rbrack^{3 +}$ | IV. | 26,600 | |
Chromium (III) Complexes
$(\mathbf{en} =$ ethylene diamine $)$
Choose the correct answer from the options given below :
Options
A.A-I, B-II, C-III, D-IV
B.A-II, B-III, C-IV, D-I
C.A-III, B-IV, C-I, D-II
D.A-IV, B-I, C-II, D-III
Solution
Sol. [Key Concept: $\Delta_{0}$ (CFSE) follows ligand-field strength: ${CN}^{-} > en > H_{2}O > F^{-}$.]
CFSE is proportional to strength of ligand followed by chelation.
${CN}^{-}$is stronger ligand than en
$${CN}^{-} > en > H_{2}O > F^{-} $$
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