Chemical Kinetics and Nuclear ChemistryMedium

Question

$t_{100\%}$ is the time required for the $100\%$ completion of the reaction while $t_{1/2}$ is the time required for $50\%$ of the reaction to be completed. Which of the following option correctly represents the relation between $t_{100\%}$ and $t_{1/2}$ for zero and first order reactions respectively?

Options

A.$t_{100\%} = \left( t_{1/2} \right)^{2}$ and $t_{100\%} = \left( t_{1/2} \right)^{- \infty}$
B.$t_{100\%} = 2t_{1/2}$ and $t_{100\%} = \left( t_{1/2} \right)^{\infty}$
C.$t_{100\%} = 2t_{1/2}$ and $t_{100\%} = \left( 2t_{1/2} \right)^{2}$
D.$t_{100\%} = \left( t_{1/2} \right)^{\infty}$ and $t_{100\%} = 2t_{1/2}$

Solution

Sol. [Key Concept: Zero order: $t_{100\%} = 2t_{1/2}$; first order: $t_{100\%} = \infty = (t_{1/2})^{\infty}$.]

Zero -order

$$t_{100\%} = \frac{a}{k};t_{1/2} = \frac{a}{2k}t_{100\%} = 2t_{1/2}$$

Ist order

$${t_{100\%} = \infty }{t_{1/2} = \frac{\mathcal{l}n2}{k} }{t_{100\%} = \left( t_{1/2} \right)^{\infty} }$$

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