Chemical Kinetics and Nuclear ChemistryMedium
Question
$t_{100\%}$ is the time required for the $100\%$ completion of the reaction while $t_{1/2}$ is the time required for $50\%$ of the reaction to be completed. Which of the following option correctly represents the relation between $t_{100\%}$ and $t_{1/2}$ for zero and first order reactions respectively?
Options
A.$t_{100\%} = \left( t_{1/2} \right)^{2}$ and $t_{100\%} = \left( t_{1/2} \right)^{- \infty}$
B.$t_{100\%} = 2t_{1/2}$ and $t_{100\%} = \left( t_{1/2} \right)^{\infty}$
C.$t_{100\%} = 2t_{1/2}$ and $t_{100\%} = \left( 2t_{1/2} \right)^{2}$
D.$t_{100\%} = \left( t_{1/2} \right)^{\infty}$ and $t_{100\%} = 2t_{1/2}$
Solution
Sol. [Key Concept: Zero order: $t_{100\%} = 2t_{1/2}$; first order: $t_{100\%} = \infty = (t_{1/2})^{\infty}$.]
Zero -order
$$t_{100\%} = \frac{a}{k};t_{1/2} = \frac{a}{2k}t_{100\%} = 2t_{1/2}$$
Ist order
$${t_{100\%} = \infty }{t_{1/2} = \frac{\mathcal{l}n2}{k} }{t_{100\%} = \left( t_{1/2} \right)^{\infty} }$$
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