Chemical Kinetics and Nuclear ChemistryHard
Question
In the gas phase, two butadiene molecules can dimerize to give larger molecules according to the reaction 2C4H6(g) → C8H12(g). The rate law for this reaction is r = K[C4H6]2 with K = 6.1 × 10−2 L mol−1 s−1 at the temperature of reaction. The rate of formation of C8H12 when the concentration of C4H6 is 0.02 M is
Options
A.2.44 × 10−5 Ms−1
B.1.22 × 10−5 Ms−1
C.1.22 × 10−3 Ms−1
D.2.44 × 10−6 Ms−1
Solution
$r = r_{C_{8}H_{12}} = K.\left\lbrack C_{4}H_{6} \right\rbrack^{2}$
$= \left( 6.1 \times 10^{- 2}\text{ }\text{M}^{- 1}s^{- 1} \right) \times \left( 0.02\text{ M} \right)^{2} $$$= 2.44 \times 10^{- 5}\text{ M }\text{s}^{- 1}$$
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