Coordination CompoundMediumBloom L1
Question
On treatment of [Ni(NH3)4]2+ with concentrated HCl, two compounds I and II having the same formula, [NiCl2(NH3)2] are obtained, I can be converted into II by boiling with dilute HCl. A solution of I reacts with oxalic acid to form [Ni(C2O4)(NH3)2] whereas II does not react. Point out the correct statement of the following
Options
A.I cis, II trans; both tetrahedral
B.I cis, II trans; both square planar
C.I trans, II cis; both tetrahedral
D.I trans, II cis; both square planar
Solution
Sol. Only Cis from react with oxalic acid to form [Ni(C2O4)(NH3)2]
Create a free account to view solution
View Solution FreeMore Coordination Compound Questions
The correct crystal field splitting and electron distribution is...Which of the following statements are correct for the complex [Co(NH3)4(Cl) (NO2)]Cl ?1. Cobalt is in +III oxidation sta...A complex [Col6]n+ where L is netural ligand has a magnetic moment μ = 4.5 B. M.Hence...The EAN of metal atoms in Fe(CO)2(NO)2 and Co2(CO)8 respectively are...Trioxalatoaluminate(III) and tetrafluoro-borate(III) ions are:...