Coordination CompoundHardBloom L3

Question

The molar ionic conductance of the octahedral complexes.

(I) PtCl4·5NH3 (II) PtCl4·4NH3 (III) PtCl4·3NH3 (IV) PtCl4·2NH3

Options

A.I < II < III < IV
B.IV < III <II < I
C.III < IV < II < I
D.IV < III < I < II

Solution

Sol. (I) PtCl4·5NH3 ⇒ [Pt(NH3)5Cl]Cl3 ⇒ It will give 4 ions

(II) PtCl4·4NH3 ⇒ [Pt(NH3)4Cl2]Cl2 ⇒ It will give 3 ions

(III) PtCl4·3NH3 ⇒ [Pt(NH3)3Cl3]Cl ⇒ It will give 2 ions

(IV) PtCl4·2NH3 ⇒ [Pt(NH3)2Cl4] ⇒ It will not ionise

Number of ions increases ⇒ molar conductance increases

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