Coordination CompoundHard
Question
Arrange the following in order of decreasing number of unpaired electrons?
I : [Fe(H2O)6]2+ II : [Fe(CN)6]3- III : [Fe(CN)6]4- IV : [Fe(H2O)6]3+
I : [Fe(H2O)6]2+ II : [Fe(CN)6]3- III : [Fe(CN)6]4- IV : [Fe(H2O)6]3+
Options
A.IV, I, II, III
B.I, II, III, IV
C.III, II, I, IV
D.II, III, I, IV
Solution
(I) [Fe(H2O)6]2+, 3d6 
n = 4 (weak field ligand)
(II) [Fe(CN)6]3-, 3d5
n = 1 (strong field ligand)
(III) [Fe(CN)6]4-, 3d6
n = 0 (strong field ligand)
(IV) [Fe(H2O)6]3-, 3d5
n = 5 (weak field ligand)
n = 4 (weak field ligand)(II) [Fe(CN)6]3-, 3d5
n = 1 (strong field ligand) (III) [Fe(CN)6]4-, 3d6
n = 0 (strong field ligand) (IV) [Fe(H2O)6]3-, 3d5
n = 5 (weak field ligand)Create a free account to view solution
View Solution FreeMore Coordination Compound Questions
Consider the transition metal ions ${Mn}^{3 +},{Cr}^{3 +},{Fe}^{3 +}$ and ${Co}^{3 +}$ and all form low spin octahedral ...The IUPAC name of Xe [Pt F6] is...In which of the following pairs both the complexes show optical isomerism ?...The IUPAC name of the Wilkinson's catalyst [RhCl(PPh3)3] is...(CFSE = Crystal Field stasilisation energy )The correct relation of x1 and x2 are :-...