Coordination CompoundHard
Question
Arrange the following in order of decreasing number of unpaired electrons?
I : [Fe(H2O)6]2+ II : [Fe(CN)6]3- III : [Fe(CN)6]4- IV : [Fe(H2O)6]3+
I : [Fe(H2O)6]2+ II : [Fe(CN)6]3- III : [Fe(CN)6]4- IV : [Fe(H2O)6]3+
Options
A.IV, I, II, III
B.I, II, III, IV
C.III, II, I, IV
D.II, III, I, IV
Solution
(I) [Fe(H2O)6]2+, 3d6 
n = 4 (weak field ligand)
(II) [Fe(CN)6]3-, 3d5
n = 1 (strong field ligand)
(III) [Fe(CN)6]4-, 3d6
n = 0 (strong field ligand)
(IV) [Fe(H2O)6]3-, 3d5
n = 5 (weak field ligand)
n = 4 (weak field ligand)(II) [Fe(CN)6]3-, 3d5
n = 1 (strong field ligand) (III) [Fe(CN)6]4-, 3d6
n = 0 (strong field ligand) (IV) [Fe(H2O)6]3-, 3d5
n = 5 (weak field ligand)Create a free account to view solution
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