Coordination CompoundMediumBloom L1
Question
In the formula of brown ring complex [Fe(H2O)5(NO)]SO4, the magnetic moment is 3.87 B.M.
The oxidation state of Fe and number of unpaired electrons present respectively are:
Options
A.1+, 3
B.2+, 3
C.3+, 3
D.3+, 5
Solution
Sol. Brown ring complex = [Fe(H2O5)NO]SO4
M.M. = 3.87 B.M
number of unpaired e– = 3
Oxidation state of C.M.A ⇒ x + 0 + 1 = 2
x = +1
NO is present in form of NO+
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