Momentum and CollisionHardBloom L3
Question
If both the blocks as shown in the given arrangement are given together a horizontal velocity towards right. If acm be the subsequent acceleration of the centre of mass of the system of blocks then acm equals
Options
A.0 m/s2
B.m/s2
C.m/s2
D.2 m/s2
Solution
Sol. 
Fext = fk = μN = 0.2 × 30 = 6N
∴ acm = $\frac{6}{3}$ = 2 m/s
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