Properties of matterMedium
Question
n drops of a liquid, each with surface energy E, joining to form a single drop
Options
A.some energy will be released in the process
B.some energy will be absorbed in the process
C.the energy released or absorbed will be E(n - n2/3)
D.the energy released or absorbed will be nE (22/3 - 1)
Solution
E = T 4πr2 ⇒ 
πR3 = n × 
⇒ n = 
⇒ R = n1/3r
Surface energy of big drop E′ = T4πR2 = T4πn2/3r2 = En2/3
Energy released = nE - E′ = nE-n2/3E = E(n-n2/3)
πR3 = n × ⇒ n = ⇒ R = n1/3rSurface energy of big drop E′ = T4πR2 = T4πn2/3r2 = En2/3
Energy released = nE - E′ = nE-n2/3E = E(n-n2/3)
Create a free account to view solution
View Solution FreeMore Properties of matter Questions
The radius of a soap bubble is r. The surface tension of soap solution is T. Keeping temperature constant, the radius of...For constant hydraulic streess on an object, the fractional change in the object′svolume (ᐃV/ V) and its bul...A brass rod of cross-sectional area 1 cm2 and length 0.2 m is compressed lengthwise by a weight of 5 kg. If Young′...Water rises to a height h in a capillary at the surface of earth. On the surface of the moon the height of water columm ...If S is stress and Y is Young′s modulus of material of a wire, the energy stored in the wire per unit volume is...