Momentum and CollisionHardBloom L3
Question
An isolated particle of mass m is moving in horizontal plane (x – y), along the x-axis, at a certain height above the ground. It suddenly explodes into two fragments of masses $\frac{m}{4}$and $\frac{3m}{4}$. An instant later, the smaller fragment is at y = +15 cm. The larger fragment at this instant is at :
Options
A.y = –5 cm
B.y = +20 cm
C.y = +5 cm
D.y = –20 cm
Solution
Sol.
$\frac{m}{4} \times 15 = \frac{3m}{4} \times y \Rightarrow y = 5$
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