Rotational MotionMedium
Question
A circular disc rotating with frequency f0 = 1.3 rev/sec comes to a stop in 30 seconds. The approximate angular acceleration is :
Options
A.+ 0.27rad/ sec2
B.- 0.27rad/ sec2
C.+0.54 rad sec2
D.+ 0.27rad/ sec2
Solution
Given, ω0 2πf = 2π × 13. = 2.6π rad / s
Using I equation of motion
ω = ω0 = αt
0 = 2.6π + α × 30
⇒ α =
- 0.27 rad / s2
Using I equation of motion
ω = ω0 = αt
0 = 2.6π + α × 30
⇒ α =
- 0.27 rad / s2Create a free account to view solution
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