Atomic StructureHard

Question

The wavelength of the first line of Lyman series for hydrogen atom is equal to that of thesecond line of Balmer series for a hydrogen like ion. The automic number Z of hydrogenlike ion is

Options

A.3
B.4
C.1
D.2

Solution

The wavelength of the first line of lyman series for hydrogen atom is
      
The wavelength of the second line of Balmer series for hydrogen line ion is
     
According to question λ = λ′
⇒       
or         or   Z2 = 4     or Z = 2

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