Atomic StructureHard
Question
The wavelength of the first line of Lyman series for hydrogen atom is equal to that of thesecond line of Balmer series for a hydrogen like ion. The automic number Z of hydrogenlike ion is
Options
A.3
B.4
C.1
D.2
Solution
The wavelength of the first line of lyman series for hydrogen atom is
The wavelength of the second line of Balmer series for hydrogen line ion is
According to question λ = λ′
⇒
or
or Z2 = 4 or Z = 2
The wavelength of the second line of Balmer series for hydrogen line ion is
According to question λ = λ′
⇒
or
or Z2 = 4 or Z = 2Create a free account to view solution
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