Chemical Kinetics and Nuclear ChemistryHard
Question
$A \rightarrow D$ is an endothermic reaction occurring in three steps (elementary).
(i) $A \rightarrow B\Delta H_{i} = + ve$
(ii) $B \rightarrow C\Delta H_{ii} = - ve$
(iii) $C \rightarrow D\Delta H_{\text{iii~}} = - ve$
Which of the following graphs between potential energy ( y -axis) vs reaction coordinate ( x -axis) correctly represents the reaction profile of $A \rightarrow D$ ?
Options
A.
B.
C.
D.
Solution
Given :
$$A \rightarrow D;\Delta_{r}H = ( + )ve = E_{D} - E_{A}\therefore E_{D} > E_{A} $$Mechanism
$${A \rightarrow B;\Delta_{r}H = ( + )ve \Rightarrow E_{B} > E_{A} }{B \rightarrow C;\Delta_{r}H = ( - )ve \Rightarrow E_{C} < E_{B} }{C \rightarrow D;\Delta_{r}H = ( - )ve \Rightarrow E_{D} < E_{C} }$$
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