ElectrochemistryMedium
Question
Consider the following reduction processes :
$${{Al}^{3 +} + 3e^{-} \rightarrow Al(s),E^{\circ} = - 1.66\text{ }V }{{Fe}^{3 +} + e^{-} \rightarrow {Fe}^{2 +},E^{\circ} = + 0.77\text{ }V }{{Co}^{3 +} + e^{-} \rightarrow {Co}^{2 +},E^{\circ} = + 1.81\text{ }V }{{Cr}^{3 +} + 3e^{-} \rightarrow Cr(s),E^{\circ} = - 0.74\text{ }V }$$The tendency to act as reducing agent decreases in the order :
Options
A.$Al > Cr > {Fe}^{2 +} > {Co}^{2 +}$
B.$Al > {Fe}^{2 +} > Cr > {Co}^{2 +}$
C.$Al > Cr > {Co}^{2 +} > {Fe}^{2 +}$
D.$Cr > {Fe}^{2 +} > Al > {Co}^{2 +}$
Solution
Reducing power $\propto \frac{1}{\text{~Reduction potential~}}$
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