Chemical BondingMedium
Question
The formal changes on the atoms marked as (1) to (4) in the Lewis representation of ${HnO}_{3}$ molecule respectively are
Options
A.$+ 1,0,0, - 1$
B.$0, - 1,0, + 1$
C.$0, + 1,0, - 1$
D.$0,0, - 1, + 1$
Solution
Consider the structure of ${HNO}_{3}$
1 :- 0
2 :- (+1)
3 :- 0
4 :- (–1)
Formal charge $=$ valence e's - non bonding e's
$$- \left( \frac{\text{~bonding electrons~}}{2} \right)$$
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