Chemical BondingHard
Question
In [Ag(CN2)]-, the number of π bonds is :
Options
A.2
B.3
C.2
D.6
Solution
In one - C ≡ N, No. of π bond = 2
So in [Ag(CN2)]-, No. of π bonds = 2 × 2 = 4
So in [Ag(CN2)]-, No. of π bonds = 2 × 2 = 4
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