Chemical Kinetics and Nuclear ChemistryHard
Question
for a reaction A → B, Ea = 10 kJ mol-1, ᐃH = 5 kJ mol-1. Thus, potential energy profile for this reaction is :
Options
A.
B.
C.
D.
Solution
For reaction, A → B.
Ea = 10 kJ/mole , ᐃH = 5 kJ/mole
Rxn endothermic because ᐃH (+)
ᐃH = Ea - Eb
5 = 10 - Eb
Eab = 10 - 5 = 5 kJ/mole. Then [B].
Ea = 10 kJ/mole , ᐃH = 5 kJ/mole
Rxn endothermic because ᐃH (+)
ᐃH = Ea - Eb
5 = 10 - Eb
Eab = 10 - 5 = 5 kJ/mole. Then [B].
Create a free account to view solution
View Solution FreeTopic: Chemical Kinetics and Nuclear Chemistry·Practice all Chemical Kinetics and Nuclear Chemistry questions
More Chemical Kinetics and Nuclear Chemistry Questions
In the following graphical representation for the reaction A → B there are two types of regions :...The rate constant (K) for the reaction 2A + B → Products was found to be 2.58 × 10−5 L mol−1 s−1 after 15 s,2.59 × 10−5 ...Hydrogen bomb is based on the principle of...For the second-order reaction A + B → Products, the rate constant k, is given as$k = \frac{2.303}{(a - b)t}\log\frac{b(a...Assuming that the charged particles emitted during natural decay of 92U235 atoms are a and b particles only, which of th...