For two reactions $A\overset{\quad K_{1}\quad}{ ightarrow}P ext{ and }B\overset{\quad K_{2}\quad}{

Question

For two reactions $A\overset{\quad K_{1}\quad}{ightarrow}P	ext{ and }B\overset{\quad K_{2}\quad}{ightarrow}Q$ of first and second order, respectively, if the initial concentrations of A and B are same (1 M), then the time taken by A and B to reach at 0.5 M concentration is same. Which of the following is/are correct statement(s) regarding the reactions?

Accepted Answer

$A\overset{\quad K_{1}\quad}{\rightarrow}P;t_{1/2} = \frac{0.693}{K_{1}}$

$B\overset{\quad K_{2}\quad}{\rightarrow}Q;t_{1/2} = \frac{1}{K_{2}\left\lbrack B_{0} \right\rbrack} = \frac{1}{K_{2}}$

From question, $\frac{0.693}{K_{1}} = \frac{1}{K_{2}} \Rightarrow K_{2} > K_{1}$

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