Chemical Kinetics and Nuclear ChemistryHard
Question
For irreversible elementary reactions in parallel $A\overset{\quad K_{1}\quad}{\rightarrow}R\text{ and }A\overset{\quad K_{2}\quad}{\rightarrow}S$, the rate of disappearance of reactant ‘A’ is
Options
A.(k1 − k2)CA
B.(k1 + k2)CA
C.1/2 (k1 + k2)CA
D.k1CA
Solution
$r_{A} = \left( - \frac{d\lbrack A\rbrack}{dt} \right)_{1} + \left( - \frac{d\lbrack A\rbrack}{dt} \right)_{2} = K_{1}\lbrack A\rbrack + K_{2}\lbrack A\rbrack = \left( K_{1} + K_{2} \right).\lbrack A\rbrack$
Create a free account to view solution
View Solution FreeTopic: Chemical Kinetics and Nuclear Chemistry·Practice all Chemical Kinetics and Nuclear Chemistry questions
More Chemical Kinetics and Nuclear Chemistry Questions
The energies of activation for forward and reverse reactions for A2 + B2 ⇋ 2AB are 180 kJ mol-1 2AB are 180 kJ mol...The hypothetical reaction : 2A + B → C + D is catalyzed by E as indicated in the possible mechanism below -Step-I ...α - Particles can be detected using...Incorrect order of solubility is :...For an endothermic reaction, energy of activation is Ea and enthalpy of reaction is ᐃH (both of these in KJ/mol). ...