Chemical Kinetics and Nuclear ChemistryMedium
Question
The half-life for the first-order reaction H2O2(aq) → H2O(l) + ½O2(g) is 30 minutes. If the volume of O2(g) collected is 100 ml after a long time, then the volume of O2(g) collected (at the same pressure and temperature) after 60 minutes from the start of reaction is
Options
A.25 ml
B.12.5 ml
C.75 ml
D.50 ml
Solution
$t = \frac{t_{1/2}}{\log 2}.\log\frac{V_{\infty}}{V_{\infty} - V_{t}}$
$\Rightarrow 60 = \frac{30}{\log 2}.\log\frac{100}{100 - V_{t}} $$$\therefore V_{t} = 75\text{ min}$$
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