Chemical Kinetics and Nuclear ChemistryHard
Question
The reaction A → B follows first order kinetics. The time taken for 0.8 mol of A to produce 0.6 mol of B is 1 hr. What is the time taken for the conversion of 0.9 mol of A to product 0.675 mol of B ?
Options
A.1 hr
B.0.5 hr
C.0.25 hr
D.2 hr
Solution
Time for the conversion of 0.8 mol of A to 0.6 mol of
B =
= 0.75 = t75%
Similarly, time for the conversion of 0.9 mol of A to 0.675 mol of
B =
= 0.75 = t75%
Hence, t75% in both case = 1 hr
B =
Similarly, time for the conversion of 0.9 mol of A to 0.675 mol of
B =
Hence, t75% in both case = 1 hr
Create a free account to view solution
View Solution FreeTopic: Chemical Kinetics and Nuclear Chemistry·Practice all Chemical Kinetics and Nuclear Chemistry questions
More Chemical Kinetics and Nuclear Chemistry Questions
Given the following second order reactions occuring at a certain temperature (T1) :-(i) A + B products(ii) C + D product...t1/4 can be taken as the time taken for the concentration of a reactant to drop to of its initial value. If the rate con...A certain reaction A → B follows the given concentration (Molarity)-time graph. Which of the following statements ...If the rate constant of a reaction is $0.03{\text{ }s}^{- 1}$, how much time does it take for $7.2\text{ }mol{\text{ }L}...Mechanism of a hypothetical reaction X2 + Y2 → 2XY is given below : (i) X2 → X + X(fast) (ii) X + Y2 ⇌...