Chemical Kinetics and Nuclear ChemistryHard
Question
The reaction A → B follows first order kinetics. The time taken for 0.8 mol of A to produce 0.6 mol of B is 1 hr. What is the time taken for the conversion of 0.9 mol of A to product 0.675 mol of B ?
Options
A.1 hr
B.0.5 hr
C.0.25 hr
D.2 hr
Solution
Time for the conversion of 0.8 mol of A to 0.6 mol of
B =
= 0.75 = t75%
Similarly, time for the conversion of 0.9 mol of A to 0.675 mol of
B =
= 0.75 = t75%
Hence, t75% in both case = 1 hr
B =
Similarly, time for the conversion of 0.9 mol of A to 0.675 mol of
B =
Hence, t75% in both case = 1 hr
Create a free account to view solution
View Solution FreeTopic: Chemical Kinetics and Nuclear Chemistry·Practice all Chemical Kinetics and Nuclear Chemistry questions
More Chemical Kinetics and Nuclear Chemistry Questions
When the concentration of reactant in the reaction A → B is increased by 8 times, the rate increases only by 2 times. Th...Which of the following plots in correctly representing the variation in rate of vaporation and rate of condensation with...In gaseous reactions important for the understanding of the upper atmosphere H2O and O react bimolecularly to form two O...What is ᐃH for the reaction A + B → C, where the mechanism involves several kinetic steps....Correct order of polarising power is :-...