Chemical Kinetics and Nuclear ChemistryHard
Question
If t1/2 of a second-order reaction is 1.0 h. After what time, the amount will be 25% of the initial amount?
Options
A.1.5 h
B.2 h
C.2.5 h
D.3 h
Solution
$100\overset{\quad 1.0\text{ hr}\quad}{\rightarrow}50\overset{\quad 2.0\text{ hr}\quad}{\rightarrow}25\text{ as }t_{1/2} = \frac{1}{K\left\lbrack A_{0} \right\rbrack}$
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