Chemical Kinetics and Nuclear ChemistryHard
Question
If t1/2 of a second-order reaction is 1.0 h. After what time, the amount will be 25% of the initial amount?
Options
A.1.5 h
B.2 h
C.2.5 h
D.3 h
Solution
$100\overset{\quad 1.0\text{ hr}\quad}{\rightarrow}50\overset{\quad 2.0\text{ hr}\quad}{\rightarrow}25\text{ as }t_{1/2} = \frac{1}{K\left\lbrack A_{0} \right\rbrack}$
Create a free account to view solution
View Solution FreeTopic: Chemical Kinetics and Nuclear Chemistry·Practice all Chemical Kinetics and Nuclear Chemistry questions
More Chemical Kinetics and Nuclear Chemistry Questions
Order of reactivity is :-...Select the correct statement(s) from the following....In the transformation of if one emission is an α-particle, what should be the other emission(s)?...Zn + 2 H+ → Zn2+ + H2Half-life period is independent of concentration of zinc at constant pH. For the constant con...Which of the following statement(s) is/are correct ?...