For a certain reaction of order ‘n’, the time for half change t1/2 is given by $t_{1/2} = \frac{\lef

Question

For a certain reaction of order ‘n’, the time for half change t1/2 is given by $t_{1/2} = \frac{\left\lbrack 2 - \sqrt{2} ightbrack}{k} 	imes C_{0}^{1/2}$, where k is the rate constant and C0 is the initial concentration. The value of n is

Accepted Answer

$1 - n = \frac{1}{2} \Rightarrow n = \frac{1}{2}$

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