ThermodynamicsHard

Question

The change in entropy accompanying the heating of one mole of helium gas (Cv,m = 3R/2), assumed ideal, from a temperature of 250 K to a temperature of 1000 K at constant pressure is (ln 2 = 0.7)

Options

A.4.2 cal/K
B.7.0 cal/K
C.2.1 cal/K
D.3.5 cal/K

Solution

$\Delta S = n.C_{P,m}.\ln\frac{T_{2}}{T_{1}} = 1 \times \frac{5R}{2} \times \ln\frac{1000}{250} = 7.0\text{ cal/K}$

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