ThermodynamicsHard

Question

What is the change in internal energy when a gas contracts from 325 ml to 125 ml at a constant pressure of 2 bar, while at the same time being cooled by removing 124 J heat?

Options

A.−524 J
B.−84 J
C.−164 J
D.+84 J

Solution

$q = - 124\text{ J and w=} - P.\Delta V = - 2\text{ bar}(125 - 325)\text{ ml}$

$= + 400\text{ bar-ml = }\frac{40}{1000} \times 100 = 40J $$$\therefore\Delta\text{U=q+w=}( - 124) + 40 = - 84\text{ J}$$

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