ThermodynamicsHard
Question
The efficiency of a Carnot cycle is 1/6. On decreasing the temperature of the sink by 65°C, the efficiency increases to 1/3. The temperature of source is
Options
A.117°C
B.52°C
C.390°C
D.1755°C
Solution
$\eta = 1 - \frac{T_{C}}{T_{H}}$
$\frac{1}{6} = 1 - \frac{T_{C}}{T_{H}}\text{ and }\frac{1}{3} = 1 - \frac{T_{C} - 65}{T_{H}} \Rightarrow T_{H} = 390\text{ K} $$$\text{=11}\text{7}^{o}C$$
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