ThermodynamicsHard

Question

The efficiency of a Carnot cycle is 1/6. On decreasing the temperature of the sink by 65°C, the efficiency increases to 1/3. The temperature of source is

Options

A.117°C
B.52°C
C.390°C
D.1755°C

Solution

$\eta = 1 - \frac{T_{C}}{T_{H}}$

$\frac{1}{6} = 1 - \frac{T_{C}}{T_{H}}\text{ and }\frac{1}{3} = 1 - \frac{T_{C} - 65}{T_{H}} \Rightarrow T_{H} = 390\text{ K} $$$\text{=11}\text{7}^{o}C$$

Create a free account to view solution

View Solution Free
Topic: Thermodynamics·Practice all Thermodynamics questions

More Thermodynamics Questions

A sample of perfect gas that initially occupies 15.0 L at 300 K and 1.0 bar is compressed isothermally. To what volume m...The heat capacity of liquid water is 75.6 J/K-mol, while the enthalpy of fusion of ice is 6.0 kJ/mol. What is the smalle...A thermodynamic property is that physical quantity...An ideal monoatomic gas undergoes a reversible process, where $\frac{P}{V}$ = constant, from (2 bar, 273 K) to 4 bar. Th...For a spontaneous process, entropy:...